Radial force on a particle with circular motion

AI Thread Summary
A particle with a mass of 0.014 kg is moving in circular motion with a radius of 0.9 m and a rotational velocity of 36 + 5*t rad/s. Over 4.8 seconds, it completes approximately 36.69 revolutions, calculated by integrating the rotational velocity. The radial force at this time is determined using the formula Fr = m * ra, resulting in a value of 45.36 N. The total force magnitude also includes linear acceleration, calculated to be 0.063 N, leading to a combined force of approximately 45.36 N. The discussion highlights confusion regarding the direction of the radial force, suggesting that clarification on this aspect may be necessary.
Lee333
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A particle of mass 0.014 kg is traveling on a radius 0.9m at a rotational velocity of 36+5*t rad.s-1.


How many revolutions does the particle go thorugh in 4.8 seconds? [revs]


What is the radial force on the particle at 4.8 seconds? [N] (Hint: consider directions)
(question I'm stuck on)


What is the absolute magnitude of force on the particle at 4.8 seconds? [N]



We know that the radial acceleration = v^2/r



To find the amount of revolutions I simply integrated the rotational velocity with respect to time, and found that the particle rotated 230.4 radians or 36.69 revs.

The second question is the question that I seem to be getting wrong. The way I tried to solve it was by firstly finding the rotational velocity after 4.8 seconds:
w = 36+5*4.8
= 60 rad/s

thus we know that the translational velocity is:
v= rw
= 60*0.9
= 54 m/s

we know that the radial acceleration, ra, can be defined by:
ra = v^2/r
= 54^2/0.9
= 3240

thus the radial force, Fr, is:
Fr = m*ra
=0.014*3240
=45.36 N

the above question i am getting wrong for some reason. any help would be appreciated




For the final question we know that the angular acceleration is 5 rad/s^2
this means the linear acceleration of the particle is 4.5 m/s.

we know the translational force will be Ft=m*a
Ft = 0.014*4.5
= 0.063

So we can work out the total magnitude of the force like so:
F_tot = sqrt(0.063^2+45.36^2)
= 45.36
 
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hi lee, welcome to physicsforums :)
Your answer looks good to me. Maybe they also wanted the direction of the radial force at that time.
 
Thanks for answering, I think its got something to do with the consider directions hint, but I am not sure what I've done wrong. I don't think they want the direction of the radial force because they didn't give a starting position for the particle, so we don't know the direction of the force.
 
ah, that's true, they don't give the starting position. Then maybe you are meant to give the direction of the radial force, compared to its direction at t=0 ? This is a bit of a stretch, but I can't imagine what else they want for the answer...
 
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