Radial Schwarzschild geodesics - again

Click For Summary

Discussion Overview

The discussion revolves around the calculation of the initial radius \( R_0 \) for a radial light ray that reaches the singularity simultaneously with a radially free-falling object starting from a radius \( r_0 \) with an initial velocity \( v \). The scope includes theoretical considerations of Schwarzschild coordinates and geodesics in general relativity.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant poses a question about deriving a simple expression for \( R_0 \) in terms of \( r_0 \) and \( v \) to determine the conditions under which both the light ray and the free-falling object reach the singularity simultaneously.
  • Another participant inquires about the time coordinate being used, suggesting that Schwarzschild coordinate time is likely appropriate since both starting points are outside the event horizon.
  • A subsequent reply confirms that \( r \), \( R \), and \( t \) are indeed Schwarzschild coordinates.
  • One participant suggests converting to ingoing Eddington-Finkelstein coordinates to simplify the analysis, noting that one of the coordinates will remain constant for an ingoing light ray, which could help determine when the light beam must have started.
  • This participant references a previous analysis related to free-fall conditions from rest at infinity and mentions the need to convert back to Schwarzschild coordinates for the final answer.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the method for calculating \( R_0 \), and multiple approaches are discussed without resolution.

Contextual Notes

The discussion involves assumptions about the choice of coordinates and the nature of the geodesics, which may affect the calculations. There is also a reference to previous analyses that may not be fully detailed in this thread.

tom.stoer
Science Advisor
Messages
5,774
Reaction score
174
Suppose there is a radially free falling object starting at r(t=0) = r0 > rS with some initial velocity v. And suppose there is a radial light ray starting at R(t=0) = R0 > r0.

Suppose that both the object and the light ray reach the singularity at the same time.

Question: is there a simple expression to calculate R0 in terms of r0 and v?

In other words: from which radius R0 must a radial light ray start in order to reach the singularity together with a radial free fall observer starting at r0 with initial velocity v?

Another equivalent question: which maximal sphere defined by R0 can be observed by an astronaut falling towards the singularity starting at starting at r0 with initial velocity v?
 
Physics news on Phys.org
tom.stoer said:
Suppose there is a radially free falling object starting at r(t=0) = r0 > rS with some initial velocity v. And suppose there is a radial light ray starting at R(t=0) = R0 > r0.

Which t coordinate are you using? Since both starting points are outside the horizon, I would assume Schwarzschild coordinate time?
 
Yes, r, R and t are Schwarzschild coordinates
 
The simplest way I know if is to convert to ingoing eddington finklestein coordinates. Then one of the coordinates (u or v, I'd have to look it up) will be constant for an ingoing light ray. Finding the value of this coordinate when the object reaches the singularity tells you when the light beam must have started (because the coordinate is constant everywhere along the ingoing geodesic).

Looking up a previous post the coordinate is u, and I did some analysis in https://www.physicsforums.com/showpost.php?p=4197343&postcount=334 for the infall equations for the case E=0, which corresponds to a free-fall from at rest at infinity.

You'll have to convert back to Schwarzschild coordinates to get the answer to your original question in Schwarzschild coordinates, however.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 55 ·
2
Replies
55
Views
8K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K