Radiation Dose Rate from 60Co γ-Ray Source

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SUMMARY

The discussion focuses on calculating the radiation dose rate from a 60Co γ-ray source with an activity of 109 Bq, positioned 3 meters away from individuals. The relevant formula for dose rate is dDose/dt = AE/r2, where A represents activity, E denotes photon energy, and r is the distance from the source. The participants clarify that the β particle, with a maximum energy of 0.3 MeV and a range of 0.8 m, does not reach the individuals at 3 m, while the γ rays of 1.2 MeV and 1.3 MeV contribute to the dose rate. The discussion emphasizes the need for proper conversion to estimate the radiation dose rate accurately, considering the exposure rate and the geometry of the source.

PREREQUISITES
  • Understanding of radiation physics, specifically γ-ray and β particle interactions.
  • Familiarity with the inverse square law in radiation dose calculations.
  • Knowledge of the concepts of activity (Bq) and energy (MeV) in radioactive decay.
  • Basic grasp of dose rate calculations and exposure rate definitions.
NEXT STEPS
  • Study the principles of radiation dose calculations using the formula dDose/dt = AE/r2.
  • Learn about the differences between exposure rate and dose rate in radiation safety.
  • Research the effects of γ radiation on human tissue and the factors influencing absorption rates.
  • Explore the concept of Bremsstrahlung and its relevance in radiation interactions.
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Students in nuclear physics, health physicists, and professionals involved in radiation safety and dosimetry who need to understand the implications of radiation exposure from γ-ray sources.

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Homework Statement


Some people are standing at a distance of 3 m from an unshielded 60Co γ-ray source of activity
10^9 Bq. What radiation dose rate are they receiving? (Each disintegration of 60Co produces a
β particle of 0.3 MeV maximum energy with a range 0.8 m in air, and two γ rays, one of 1.2 MeV and one of 1.3 MeV, in quick cascade).


Homework Equations



dDose/dt = AE/r^2

A = activity
E = energy of photons
r = distance from source


The Attempt at a Solution



I'm at a bit of a loose end with this question as I've not been given any guidance - perhaps someone could suggest a relevant website to explain?
Due to the Beta particle traveling only 0.8m does this mean it doesn't reach the people standing 3m away? or does it decay into other particles?
Do i at some point calculate the flux of the rays? as i put the r^2 term in as i assumed it to be like a point source and diverging away (thus a 1/r^2 relation)

Thanks for any help and guidance on this question!
 
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Due to the Beta particle traveling only 0.8m does this mean it doesn't reach the people standing 3m away?
Right. An electron is an elementary particle, it cannot decay. It can produce Bremsstrahlung (photons), but that can be neglected I think - even if its total energy would be converted to Bremsstrahlung, 0.3 MeV << (1.2 MeV + 1.3 MeV).

as i put the r^2 term in as i assumed it to be like a point source and diverging away (thus a 1/r^2 relation)
That is fine for the radiation per area. You might need some additional conversion to get a radiation dose rate for those humans.
 
Ok... so do i just multiply it by the approximate area of a human?

I would have Radiation/area * area(of human) = radiation dose/per time(comes from the activity)
 
If humans absorb every photon which hits them, right. As an upper estimate, this should be fine.
 
This is a poorly worded question and you should tak your instructor (or the editor of the book) to task. The formula is (usually) the exposure rate, not the dose rate since not all gammas that pass through the body will be absorbed completely. In addition, the inverse square law applies only to point particles or geometries that approximate point particles.
 

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