Radioactive decay. Is energy released? OPINION PLEASE

AI Thread Summary
Radioactive decay does release energy, even though the total number of nucleons remains constant before and after the decay. Energy is emitted in the form of gamma radiation, kinetic energy of alpha or beta particles, and the kinetic energy of the resulting elements. The decay of radium-226 into radon-222 and an alpha particle illustrates this, as the masses of the products are lighter, indicating mass conversion to energy. The discussion emphasizes that gamma rays, being massless, do not affect the overall mass but still represent energy release. Thus, the consensus is that energy is indeed released during radioactive decay.
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[SOLVED] Radioactive decay. Is energy released? OPINION PLEASE!

This is my last question in my last Physics exam!
YES! I'M ALMOST DONE! :smile:

I would just like your opinion on this question...
My answer is Yes... But sometimes I think it should be NO because
of the question's option for a No answer. But from what I understand
in the textbook, the answer should be YES.

1. THE QUESTION:

The decay of \frac{226}{88}Ra results in the release of some energy. Your book tells you that energy
is released in a nuclear reaction when mass is changed to energy. Yet there are the same
number of nucleons before the decay as there are after the decay. Is energy released
in this reaction without a conversion of mass? If not, what mass is converted?
2. MY ANSWER:

Yes, energy is released in this reaction even though the total amount of nucleons in the two new atoms are still the same. Why? Well, the textbook says that when an element transmutates, energy is released in three forms: gamma radiation, the kinetic energy of the alpha or beta particle, and the kinetic energy of the new element. In addition, gamma radiation is massless energy. So if the radium particle emitted gamma rays, its mass would not be affected, even though energy was released.
FYI: This question is a continuation of the previous problem, which is: \frac{226}{88}Ra decays into Rn (atomic #86) and an alpha particle. Complete the reaction written below.

\frac{226}{88}Ra \Rightarrow (my answer follows) \frac{222}{86}Rn + \frac{4}{2}He
 
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If you add up the masses of the reaction products, you'll find that they are lighter. mass is converted to energy.
 
If energy isn't released then the Mayor of Hiroshima has some questions to answer about a very large insurance claim.
 
mgb_phys said:
If energy isn't released then the Mayor of Hiroshima has some questions to answer about a very large insurance claim.

lol :D
 
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