- #1

KarenRei

- 100

- 6

Just double checking this - I found this formula describing the radius of the path of an ion in a cyclotron:

R = sqrt(2*E*m)/(e*B)

.. where R is the radius in meters, E is the energy of the particle in joules, m is the mass in kilograms, c is the charge in coulombs, and B is the strength of the magnetic field in Teslas.

Is this correct, and would this be the maximal radius required for the collimation of electrons emitted from a flat surface inside an axial magnetic field? So for example, for an electron - charge -1.60e−19C, rest mass 9.11e-31kg, energy 16MeV=2.56e-12J - emitted inside say a 1T field - would curve parallel to the field lines in sqrt(2*9.11e-31*2.56⋅10e-12)/(-1.6e−19C*1) = 0.013m = 1.3cm if 100% perpendicular to the field, less otherwise?

Just making sure here :)

R = sqrt(2*E*m)/(e*B)

.. where R is the radius in meters, E is the energy of the particle in joules, m is the mass in kilograms, c is the charge in coulombs, and B is the strength of the magnetic field in Teslas.

Is this correct, and would this be the maximal radius required for the collimation of electrons emitted from a flat surface inside an axial magnetic field? So for example, for an electron - charge -1.60e−19C, rest mass 9.11e-31kg, energy 16MeV=2.56e-12J - emitted inside say a 1T field - would curve parallel to the field lines in sqrt(2*9.11e-31*2.56⋅10e-12)/(-1.6e−19C*1) = 0.013m = 1.3cm if 100% perpendicular to the field, less otherwise?

Just making sure here :)

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