Radius of Convergence for Moderately Complicated Series

LukeMiller86
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1. The problem statement:

Show that the following series has a radius of convergence equal to exp\left(-p\right)

Homework Equations



For p real:

\Sigma^{n=\infty}_{n=1}\left( \frac{n+p}{n}\right)^{n^{2}} z^{n}

The Attempt at a Solution


\stackrel{lim}{n\rightarrow\infty}\left|a_{n}\right|^{1/n} = \frac{1}{R} = \left(\frac{n+p}{n}\right)^{n}<br /> =exp\left(n\left(ln\left(\frac{n+p}{n}\right)\right)\right)

Apart from playing with the logarithm after that I cannot seem to reach the required answer.
Any help would be greatly appreciated.
 
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What's the limit definition of the exponential function?
 
exp\left(-p\right) = e^{\left(-p)\right}

is that what you meant?
 
Do you know this limit:
\lim_{n\to\infty}\left(1+\frac{p}{n}\right)^n
 
Completely overlooked that! Thanks very much.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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