Radius of convergence log(a + x)

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Homework Statement



determine the radius of convergence of the series expansion of log(a + x) around x = 0

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The Attempt at a Solution



So after applying the Taylor series expansion about x=0 we get log(a) + SUM[(-1)^n x^n/(n a^n)] I understand how to get the radius of convergence for log(1+x) for instance using the ratio test, but with 1 being replaced with what I believe to be an arbitrary constant I am now confused as to how I should tackle this, any help would be great, thanks in advance!

Would I employ the ratio test in the same way? I have a log in the numerator and denominator so not really sure...
 
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So after applying the Taylor series expansion about x=0 we get log(a) + SUM[(-1)^n x^n/(n a^n)]
There is a minor error: log(a+x)=log(a)+\sum_1^{\infty}(-1)^{n+1} \frac{x^n}{n a^n}
Do the same as with other power series.
Where do you have log in the terms of the series, except the first one?


ehild
 
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Yeah so I only have the log in the first term, that's why I am confused, just making sure it is the same as if all terms are just a power series, would I use the ratio test in the same vein as with log(1+x)?
 
Yes, use the ratio test. Do not worry about the first term. ehild
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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