1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Radius of curvature. :/

  1. Mar 23, 2009 #1
    A production line inspector wants a mirror that produces an upright image within magnification of 7.9 when it is located 10.0 mm from a machine part.
    What is its radius of curvature?




    I used:
    r/2 = f
    1/f=(1/do) + or - (1/di)
    m=di/do




    first i did 7.9=10/do
    then i found that do=1.27mm
    So then i did 1/f=1/1.27+1/10
    I got f=1.3
    Then i multiplied that by 2
    (r/2)=f
    So then i got 2.6
    I tried -2.6 for the heck of it
    and then i did it all again except i did:
    1/f=1/1.27-1/10
    and calculated it all out and it was still wrong.
    Even when it was negative.
    Argh. Help? =( Because i have 2 more like this. x.x
     
  2. jcsd
  3. Mar 23, 2009 #2

    alphysicist

    User Avatar
    Homework Helper

    Hi DDRchick,



    The question here is using the word "it" which can often cause trouble (and I think might be leading to a mistake in your work). Is it referring to the mirror's distance from the object, or the image's distance (because I've seen problems with the meaning both ways). From the wording though, I think it means that the mirror is 10mm from the object.


    I don't think there would ever be a negative sign in this formula (though sometimes do or di can be negative values).

    This formula need a minus sign:

    [tex]
    m=-\ \frac{d_i}{d_o}
    [/tex]



    d_i is the image distance (distance from image to mirror); I don't think that's what the 10mm refers to in the problem statement. I think when you change these three things you'll get the right answer (because your basic approach looks right to me).
     
  4. Mar 23, 2009 #3
    Ugh It's still wrong. :/
    Crap bucket.
    di/10=7.9
    di=79
    1/f=1/79+1/10
    f=8.88
    r/2=8.88
    8.88(2) = 17.76
    I tried it with a negative sign too just for kicks, that was marked wrong also.
    :(
     
  5. Mar 23, 2009 #4

    alphysicist

    User Avatar
    Homework Helper

    Remember that I mentioned above that this formula needs a minus sign. So di will be -79mm.

    Do you mean you just put in -17.76, or that you used the minus sign in the magnification formula? If you use di= -79mm, I believe the rest of your procedure is fine.
     
  6. Mar 25, 2009 #5
    I mean i just put in -17.76...
    Garr.
    Well thanks for your help, it was due a day ago unfortunately, but i survived aha.
    :)
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Radius of curvature. :/
  1. Radius of curvature (Replies: 5)

  2. Radius of Curvature (Replies: 1)

Loading...