Radius of Half Electric Potential Energy

AI Thread Summary
The discussion revolves around calculating the potential energy stored in a system consisting of a solid cylinder and a shell cylinder. The main challenge is determining the reference point for potential energy calculations, with confusion arising from using infinity or zero as references. Participants emphasize the importance of not mixing potential and potential energy, highlighting that the potential difference between the cylinder surfaces is crucial. The stored energy is entirely between the cylindrical surfaces, and the correct approach involves using the capacitor energy formula in relation to voltage and charge. Ultimately, the original poster resolves their confusion with assistance from others.
NiendorfPhysics
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Homework Statement



There is a solid cylinder of radius a and then empty space then a shell cylinder of radius b. Show that half of the stored potential energy lies within a cylinder of radius $$\sqrt{ab}$$

Homework Equations



In the attempt

The Attempt at a Solution


I'm not sure what they want me to calculate the potential energy with respect to. If I do it wrt infinity it is infinity, same with 0. Let's say they want me to calculate it wrt the cylinder of radius that we have yet to determine. Then the energy is (getting rid of constants since they won't matter later):
$$\frac{1}{4}+\ln{\frac{R}{a}}$$

At least for the solid cylinder of radius a. Now we add the part of the energy stored in the field from the end of a to the fake cylinder. $$ln(\frac{R}{a})$$

Now we take one half of these values and add them together and set that equal to $$ln(\frac{R}{a})$$ and nothing works and I hate it because I know all of this is wrong.

But this problem cannot be this hard. This is just an RHK problem, I must be missing something simple. Can someone put me the on the right track?
 
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NiendorfPhysics said:

Homework Statement



There is a solid cylinder of radius a and then empty space then a shell cylinder of radius b. Show that half of the stored potential energy lies within a cylinder of radius $$\sqrt{ab}$$

Homework Equations



In the attempt

The Attempt at a Solution


I'm not sure what they want me to calculate the potential energy with respect to. If I do it wrt infinity it is infinity, same with 0. Let's say they want me to calculate it wrt the cylinder of radius that we have yet to determine. Then the energy is (getting rid of constants since they won't matter later):
$$\frac{1}{4}+\ln{\frac{R}{a}}$$

At least for the solid cylinder of radius a. Now we add the part of the energy stored in the field from the end of a to the fake cylinder. $$ln(\frac{R}{a})$$

Now we take one half of these values and add them together and set that equal to $$ln(\frac{R}{a})$$ and nothing works and I hate it because I know all of this is wrong.

But this problem cannot be this hard. This is just an RHK problem, I must be missing something simple. Can someone put me the on the right track?
Do not mix potential an potential energy. The potential with respect to one surface changes proportionally with ln(R/a). So the potential difference between the surfaces of radii a and b is?
The energy is stored entirely between the cylindrical surfaces of the capacitor. You can use the formula for the energy of a capacitor in terms of voltage and charge.
 
ehild said:
Do not mix potential an potential energy. The potential with respect to one surface changes proportionally with ln(R/a). So the potential difference between the surfaces of radii a and b is?
The energy is stored entirely between the cylindrical surfaces of the capacitor. You can use the formula for the energy of a capacitor in terms of voltage and charge.
So $$U_{total} = \frac{1}{2} C (ln(\frac{b}{a}))^2$$ and $$U_{radial} = \frac{1}{2} C (ln(\frac{R}{a}))^2$$? I know this is wrong but I don't know what is right.
 
ehild said:
Do not mix potential an potential energy. The potential with respect to one surface changes proportionally with ln(R/a). So the potential difference between the surfaces of radii a and b is?
The energy is stored entirely between the cylindrical surfaces of the capacitor. You can use the formula for the energy of a capacitor in terms of voltage and charge.
Nevermind I got it thank you for the help
 
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