Radius of Half Electric Potential Energy

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SUMMARY

The discussion focuses on calculating the radius at which half of the stored electric potential energy lies within a solid cylinder of radius a and a shell cylinder of radius b. The conclusion is that this radius is given by $$\sqrt{ab}$$. Participants emphasize the importance of not confusing electric potential with potential energy and suggest using the energy formula for a capacitor, specifically $$U_{total} = \frac{1}{2} C (ln(\frac{b}{a}))^2$$, to derive the solution. The discussion highlights common pitfalls and clarifies the relationship between potential and potential energy in cylindrical geometries.

PREREQUISITES
  • Understanding of electric potential and potential energy concepts
  • Familiarity with cylindrical capacitors and their energy storage
  • Knowledge of logarithmic functions and their properties
  • Basic principles of electrostatics and capacitance
NEXT STEPS
  • Study the derivation of energy stored in cylindrical capacitors
  • Learn about the relationship between electric potential and potential energy
  • Explore the application of logarithmic functions in physics problems
  • Review examples of electric field calculations in cylindrical coordinates
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone involved in electrical engineering or capacitor design will benefit from this discussion.

NiendorfPhysics
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Homework Statement



There is a solid cylinder of radius a and then empty space then a shell cylinder of radius b. Show that half of the stored potential energy lies within a cylinder of radius $$\sqrt{ab}$$

Homework Equations



In the attempt

The Attempt at a Solution


I'm not sure what they want me to calculate the potential energy with respect to. If I do it wrt infinity it is infinity, same with 0. Let's say they want me to calculate it wrt the cylinder of radius that we have yet to determine. Then the energy is (getting rid of constants since they won't matter later):
$$\frac{1}{4}+\ln{\frac{R}{a}}$$

At least for the solid cylinder of radius a. Now we add the part of the energy stored in the field from the end of a to the fake cylinder. $$ln(\frac{R}{a})$$

Now we take one half of these values and add them together and set that equal to $$ln(\frac{R}{a})$$ and nothing works and I hate it because I know all of this is wrong.

But this problem cannot be this hard. This is just an RHK problem, I must be missing something simple. Can someone put me the on the right track?
 
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NiendorfPhysics said:

Homework Statement



There is a solid cylinder of radius a and then empty space then a shell cylinder of radius b. Show that half of the stored potential energy lies within a cylinder of radius $$\sqrt{ab}$$

Homework Equations



In the attempt

The Attempt at a Solution


I'm not sure what they want me to calculate the potential energy with respect to. If I do it wrt infinity it is infinity, same with 0. Let's say they want me to calculate it wrt the cylinder of radius that we have yet to determine. Then the energy is (getting rid of constants since they won't matter later):
$$\frac{1}{4}+\ln{\frac{R}{a}}$$

At least for the solid cylinder of radius a. Now we add the part of the energy stored in the field from the end of a to the fake cylinder. $$ln(\frac{R}{a})$$

Now we take one half of these values and add them together and set that equal to $$ln(\frac{R}{a})$$ and nothing works and I hate it because I know all of this is wrong.

But this problem cannot be this hard. This is just an RHK problem, I must be missing something simple. Can someone put me the on the right track?
Do not mix potential an potential energy. The potential with respect to one surface changes proportionally with ln(R/a). So the potential difference between the surfaces of radii a and b is?
The energy is stored entirely between the cylindrical surfaces of the capacitor. You can use the formula for the energy of a capacitor in terms of voltage and charge.
 
ehild said:
Do not mix potential an potential energy. The potential with respect to one surface changes proportionally with ln(R/a). So the potential difference between the surfaces of radii a and b is?
The energy is stored entirely between the cylindrical surfaces of the capacitor. You can use the formula for the energy of a capacitor in terms of voltage and charge.
So $$U_{total} = \frac{1}{2} C (ln(\frac{b}{a}))^2$$ and $$U_{radial} = \frac{1}{2} C (ln(\frac{R}{a}))^2$$? I know this is wrong but I don't know what is right.
 
ehild said:
Do not mix potential an potential energy. The potential with respect to one surface changes proportionally with ln(R/a). So the potential difference between the surfaces of radii a and b is?
The energy is stored entirely between the cylindrical surfaces of the capacitor. You can use the formula for the energy of a capacitor in terms of voltage and charge.
Nevermind I got it thank you for the help
 

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