Radius Vector Homework: Find Velocity, Acceleration, Time, & Distance

  • Thread starter Thread starter phisics99
  • Start date Start date
  • Tags Tags
    Radius Vector
AI Thread Summary
The radius vector of a particle is given by r=at(1-αt), where "a" is a constant vector and α is a positive factor. The velocity is calculated as v=a(1-2αt) and the acceleration as ω=-2α. To find the time interval Δt for the particle to return to its initial position, the equation r=0 is used, leading to the result t=1/α. For the distance covered during this time, standard equations of motion can be applied. The discussion emphasizes the need for clarity in applying these concepts to solve the problem effectively.
phisics99
Messages
1
Reaction score
0

Homework Statement


A radius vector of a particle varies with time t as r=at(1-\alphat) where "a" is a constant vector \alpha is a positive factor.
Find:
a) velocity "v" and the acceleration \omega as function of time;
b) the time interval \Deltat taken by the particle to return to the initial points and the distance "s" covered during this time.

I have solved a) and have problem with b)


Homework Equations



r=at(1-\alphat)
v=a(1-2\alphat)
\omega=-2\alpha

The Attempt at a Solution


To find time I should divide r/v? I don't understand that. The result is: t=1/\alpha.
Now how find distance? Substitute founded time to equation as r?
Looking for some help, my phisical english isn't so good , because come from Poland. Thx
 
Physics news on Phys.org
Welcome to PF!

Hi phisics99! Welcome to PF! :smile:

(have an alpha: α and an omega: ω :wink:)
phisics99 said:
A radius vector of a particle varies with time t as r=at(1-\alphat) where "a" is a constant vector \alpha is a positive factor.
Find:
a) velocity "v" and the acceleration \omega as function of time;
b) the time interval \Deltat taken by the particle to return to the initial points and the distance "s" covered during this time.

To find time I should divide r/v? I don't understand that. The result is: t=1/\alpha.
Now how find distance? Substitute founded time to equation as r?

(btw, your ω is missing an α :wink:)

To find time, just use the original equation, r = at(1 - αt) …

r = 0 at t = 0 and at t = … ? :smile:

(and then use one of the standard constant acceleration equations to get distance)
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top