1.What would be the effect of an increase in temperature on the rate constant of a) the forward reaction? b) the reverse reaction I assume the forward reaction rate constant would be increased due to a greater amount of kinetic energy of the reacting molecules resulting in more collisions? But I am unsure as to what would happen in the reverse reaction. Would it as well be increased since there is more kinetic energy that is converted to potential energy by the creating of new bonds??? Please correct me if I'm wrong. thanks.