Rate of rotational inertia help

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SUMMARY

The discussion centers on a figure skater's change in rotational speed due to a reduction in rotational inertia. Initially spinning at 1.6 revolutions per second (rev/s) with arms outstretched, the skater reduces her rotational inertia to 64% of its original value. According to the conservation of angular momentum, the new rate of rotation can be calculated using the formula: initial angular momentum = final angular momentum. This leads to the conclusion that the skater's new rate of rotation is 2.5 rev/s.

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jmb07
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I need some help just getting moving on this problem...

A figure skater is spinning at a rate of 1.6 rev/s with her arms outstretched. She then draws her arms in toward her chest reducing her rotational inertia to 64% of its original value. What is her new rate of rotation??

I'm not sure how to relate the rate to the inertia...
 
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jmb07 said:
I need some help just getting moving on this problem...

A figure skater is spinning at a rate of 1.6 rev/s with her arms outstretched. She then draws her arms in toward her chest reducing her rotational inertia to 64% of its original value. What is her new rate of rotation??

I'm not sure how to relate the rate to the inertia...
What is the equation which defines the angular momentum of a body?
 

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