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cmalle09
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An inductor used in a DC power supply has an inductance of 13H and a resistance of 160 ohms. It carries a current of 0.4 A. What is the stored energy in the magnetic field? At what rate is thermal energy developed in the inductor?
L=13H
R=160 ohms
I=0.4A
W = 1/2Li^2 = 1/2(13)(0.4)^2 = 1.04 J
I am unsure where to go from here. I can calculate the stored energy, but what do I do for the rate of thermal energy?
L=13H
R=160 ohms
I=0.4A
W = 1/2Li^2 = 1/2(13)(0.4)^2 = 1.04 J
I am unsure where to go from here. I can calculate the stored energy, but what do I do for the rate of thermal energy?