Ratio of gravitational/repulsive electrostatic force

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The discussion focuses on calculating the ratio of gravitational force to electrostatic force between two protons. The gravitational force formula should use the gravitational constant (G) instead of the acceleration due to gravity (g). Participants suggest leaving the radius (r) in symbolic form rather than solving for it numerically. The correct approach involves expressing both forces algebraically before finding their ratio. This method ensures clarity and accuracy in the calculations.
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Homework Statement


Calculate the ratio of the magnitude of the attractive gravitational force to the repulsive electrostatic force between two protons.

Homework Equations


Mass of proton = M = m = 1.672e-27 kg
g = 9.80665m/s2
Q = q = 1.60219e−19 C
k = 8.9875e9 N•m2/C2F_{Gravity}=g\frac{Mm}{r^{2}}

F_{electric}=k\frac{Qq}{r^{2}}

The Attempt at a Solution


The radius r is not given, so I attempted to find it algebraically by plugging in numbers, and I get:

F_{gravity}=\frac{2.74m/s^{2}\cdot kg^{2}}{r^{2}}

I feel certain I am on the wrong track.
 
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For Fgravity you should use G, not g. I.e., not 9.8 m/s2
 
Thanks, I changed g to G, but I'm still not sure what to do after solving for r
 
Don't solve for r, just leave it in the form

Fgravity = {your expression here}
Then do the same for Felectric.
 
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