RC Circuits: Graph Homework - Determine Flash Frequency & Voltage Sketch

AI Thread Summary
The discussion focuses on a blinking light circuit using a neon lamp and a 4.0uF capacitor, which charges from a 110 V power supply. The neon lamp ionizes at 75 V, allowing it to conduct and discharge the capacitor, producing a flash of light. The time constant for the circuit is calculated as 0.1 seconds, leading to a flash frequency of approximately 8.8 Hz. A voltage versus time sketch of the circuit is provided, with feedback suggesting the discharge may occur more rapidly than depicted. This circuit effectively demonstrates the principles of RC charging and discharging in practical applications.
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Homework Statement


A simple type of blinking light circuit can be constructed using a neon lamp. The circuit has a 4.0uF capacitor in parallel with a neon lamp. When the voltage is low in the RC portion of the circuit, the lamp does not conduct electricity. Therefore, it is effectively not there from an electrical point of view. The RC circuit will then charge from the 110 V power supply. However, when the voltage across the capacitor reaches 75 V, the neon will ionize very quickly and the neon lamp will become a very good conductor, and will immediately discharge the capacitor. The energy stored in the capacitor will be given off as a flash of orange light, making this a useful circuit. After the flash, the charging process will start once more since the voltage will again be low.

a) Determine the flash frequency with the resistance value shown.
b) Make a sketch of the voltage across the capacitor versus time in such a circuit, showing several periods.

Homework Equations



time constant = RC
V = Vo(1- e^ t/RC)


The Attempt at a Solution



For part a)
time constant = RC = (25 * 10^3 ohm) * (4.0 * 10^-6 F) = 0.1s

t = -ln (1- 75V/110V) * 0.1s
= 0.114s

frequency = 1/t = 8.8 Hz

For part b)
I've attached a sketch but I'm not sure if this is correct. Any help would be great!
 

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Your sketch is pretty good, if anything it may fall faster than you have shown because it says 'will immediately' discharge the capacitor.
 
technician said:
Your sketch is pretty good, if anything it may fall faster than you have shown because it says 'will immediately' discharge the capacitor.

Thanks!
 
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