Reaction between photon and proton

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SUMMARY

A high-energy proton can collide with a photon to produce a charged pion and a neutron, as described by the reaction p+ + ph → pion + n0. For a photon sourced from the cosmic microwave background with an energy equivalent to a temperature of 3 K, the minimum energy required for the proton to facilitate this reaction is calculated based on the rest mass energies of the neutron and pion. The left-hand side of the reaction must equal or exceed the energy of the right-hand side, necessitating precise energy calculations.

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  • Familiarity with energy-momentum conservation principles
  • Knowledge of rest mass energies of subatomic particles
  • Basic concepts of cosmic microwave background radiation
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programmer1115
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A high energy proton can collide with a photon to produce a charged pion and a neutron. If the photon comes from the cosmic microwave background and has an energy equivalent to a temperature of 3 K, what is the minimum energy of the proton in eV necessary to allow this reaction?

I'm thinking about momentum of a photon and stuff.. is my approach correct ? if not what should be done ?
 
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So the reaction is:
[tex]p^+ + ph \rightarrow pion + n^0[/tex]

The energy of the left handside must not be less, than that of the right handside, so you'll just have to look up the energies of the neutron and pion (zero velocity).
 

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