Reaction force of freely rotating rod

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Discussion Overview

The discussion revolves around calculating the reaction force of a homogenous rod that is free to rotate around one of its ends. Participants are exploring the implications of different conditions such as movement and gravity in relation to the rod's position.

Discussion Character

  • Exploratory, Technical explanation, Homework-related

Main Points Raised

  • One participant suggests calculating the force on the fixed point due to gravity and the movement of the rod, noting that if zero movement is assumed, the force is simply a function of the rod's position.
  • Another participant agrees with the previous suggestion but emphasizes the challenge of not assuming zero movement in their calculations.
  • A further suggestion is made to calculate the force assuming zero movement first, then to add the centripetal force to account for movement.

Areas of Agreement / Disagreement

Participants appear to agree on the need to consider both gravity and movement in their calculations, but there is no consensus on the approach to take, particularly regarding the assumption of zero movement.

rruben
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Hi guys!

I'm working some problems for our exam in a few weeks and there are a few problems we are unable to solve.

One of them is: "A homogenous rod is free to rotate without friction around one of it's ends. Find the reaction force in function of the position of the rod."

As you can see the question is very vague, we've tried to do something with Euler's angles and equations of motion but cannot get to a solution. Any input or help would be greatly appreciated!

Thanks
 
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Maybe you should calculate the force on the fixed point due to gravity and movement of the rod. If you can assume zero movement, it is just a function of the position, otherwise the angular velocity is relevant, too.
 
We think that may be right but the difficulty is how to go about something like this, not assuming zero movement of course.
 
Calculate it with zero movement, add the centripetal force.
 

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