Is an Inductor Consuming or Delivering Reactive Power?

AI Thread Summary
The discussion centers on understanding whether an inductor is consuming or delivering reactive power. It highlights the confusion surrounding the terms used in power networks and synchronous machines, particularly regarding reactive power and phase angles. The conversation explains that inductors store reactive power in their magnetic fields, which is released in a different time period, leading to the notion that they do not consume power in the traditional sense. The transient state of the circuit is also examined, noting that it arises when the voltage and current are not in sync initially. Ultimately, the distinction between consuming and delivering reactive power is emphasized, with a focus on the phase relationship between voltage and current.
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Trying to understand the power network and synchronous machines, led me to the fact that I am not sure about the basics.

The terms the generator is delivering or consuming reacting power made me halt.


So I went back to my old course(which I allegedly passed) where the reactive power is addressed. I couldn't understand that back then(1 year) because I barley handled the phase angle, let alone problems of reactive power and its true meaning.



Consider a RL circuit. Plain. (or real inductor).



Solving the differential equation(which I didn't know how to do back then) gives me this:

for u(t)=U_m\cdot sin(\omega t+\theta _u)

I get that the current is changing like:

i(t)=I_m\cdot sin(\omega t+\theta _u-\phi _L)-I_ m\cdot sin(\theta _u -\phi _L)\cdot e^{-\frac{R}{L}t}

Lets discuss this:

We have 2 components. First component represents a steady-state current.

Second component represents a transient-state which slowly fades.


My question here is:


Do we say for an inductor, that is consuming reactive power?

If we make the angle of the voltage source u(t) such that it cancels the transient-state, did we in fact, "configured" that voltage source, to give OUT reactive power, and give it out just SO much that it cancels the "needs" of that inductor?


These are the questions for now, tons of other are awaiting, but first I have to make a clear distinction between giving out and consuming reactive power.
 
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I usually forward people to this. I think it describes the differences well.
http://www.allaboutcircuits.com/vol_2/chpt_11/2.html
 
Do we say for an inductor, that is consuming reactive power?

It's all a agreement how we call that.. consuming means that the current is lagging. There is no power consumption - the reactive power is stored in inductiors magnetic field (stored in one period and moved out in another period).

If we make the angle of the voltage source u(t) such that it cancels the transient-state, did we in fact, "configured" that voltage source, to give OUT reactive power, and give it out just SO much that it cancels the "needs" of that inductor?

First of all.. where from comes the transient state ? Tranient occurs when You start from "u(t=0) not eq amplitude". Why ? When U is at it's peak I is equal to 0 (90deg phase shift, obvious). But what about reactive power ? When "q(t=0) is eq to 0" the circuit starts with no transients. At point (t=0"-") the total energy stored in inductor is zero, and there can't be a discontinous energy change.
 
es1 said:
I usually forward people to this. I think it describes the differences well.
http://www.allaboutcircuits.com/vol_2/chpt_11/2.html

Thank you for your link. Very useful.
 
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