Reactivity of solutions with the same anion

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The discussion centers on whether anions from different aqueous solutions, despite having the same concentration, exhibit different reactivities due to their associated cations and solubility differences. The example of CaF2 and NaF highlights that the reactivity of F- may vary based on the bond strengths and the ionic environment created by the cations. Participants suggest that the proximity of cations can influence the anion's behavior, even when both solutions are solvated. The concept of ionic strength and activity coefficients, as described by Debye-Hückel theory, is also mentioned as a factor in determining reactivity. Overall, the consensus leans toward the idea that reactivity is indeed dependent on the specific conditions of each solution.
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If I have two aqueous solutions of two different compounds (with different solubility) that result in equal amounts of the same anion, should the anion in those solutions have the same reactivity or not?

An example:
Solution A
CaF2 (aq)

Solution B
NaF (aq)

The solutions are prepared such that both contain the same amount of F-. Is F- more or less reactive in either of the solutions? Would it be dependent on the cations or solubility of the compound?
 
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Before we will start to discuss details - what is your opinion? Per forum rules you should try to answer the question by yourself first.
 
I'm leaning towards the idea that the reactivity would be different, perhaps due to the differing bond strengths in the compounds. Different cations in proximity to the anion would affect the anion's reactivity in ways particular to those species, despite both having been solvated.
 
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Have you heard about ionic strength of the solution and activity coefficients? Debye-Hückel theory?
 
CaF2 is practically insoluble in water.
 
Saturated CaF2 is something like 4x10-4 M in F-. Not much, but quite a reasonable concentration, easy to prepare.
 
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