Real and virtual photons via neutral pion decay

AI Thread Summary
The discussion revolves around the decay of a neutral pion into photons, focusing on conservation of energy and momentum. It is established that a neutral pion at rest can decay into two real photons, as their combined energy equals the pion's rest energy, and their momenta cancel each other out. The challenge arises when considering the decay into a single photon, which must be virtual, as it cannot satisfy both energy and momentum conservation simultaneously in the pion's rest frame. Participants suggest using conservation laws to relate the energies and momenta of the photons, emphasizing the importance of understanding the energy-momentum relationship. The conversation highlights the complexities of the problem while clarifying the necessary approach to demonstrate the decay processes.
padraux3
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I wasn't sure whether this question should go in advanced or introductory physics but I decided to post here since it doesn't involve any complex maths.

Homework Statement


Part 1
Consider a neutral pion at rest. On the basis of conservation of energy and momentum alone, show that it is possible for the pion to decay into two real photons (ie: two photons that obey the classical energy momentum relation for photons).

Part 2
Show that if a neutral pion decays into a single photon then the photon is virtual.
Hint: Consider the decay in the rest frame of the pion.

Homework Equations


Photon energy = |p|c
E = mc^2
Conservation laws

The Attempt at a Solution


I'm not sure if I've been going about this the right way but I've been trying all day.

Since the pion is at rest its energy is E(pion) = mc^2.
Then by the conservation of energy, the sum of the energies of the two photons is equal to E(pion). Also, the pion has zero momentum so the momentum of the two photons is also zero (thus they are moving at the same speed in opposite directions). From here I've tried to show that the energy of each photon is given by the first equation I listed. I know that the pion's energy should be evenly distributed between the two photons but I'm not sure how to show it.

Thanks in advance.
 
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Hi padraux3! :wink:

I think you're making this too complicated …

why derive the energy of a photon from its momentum? :confused:

just use energy of photon = h times … ? :smile:

(and I suppose techinically you have to show that all the other quantum numbers, like baryon number, are conserved :wink:)
 
Thanks for your reply.

If I use E = hf then I end up with the equation mc^2 = h(f1+f2) where fi is the frequency of the ith photon and m is the mass of the pion. I don't really understand what I need to show. From the first hint I assumed I needed to show E = |p|c for each photon so that's why I was trying to derive the energy from momentum. I can't use conservation of quantum numbers, only energy and momentum.
 
I don't think you don't need to prove the energy-momentum relation (unless this is an exercise in deriving special relativity from scratch :wink:).

padraux3 said:
I know that the pion's energy should be evenly distributed between the two photons but I'm not sure how to show it.
To show that, you can use momentum conservation in the pion's rest frame. For example, say that photon #1 has energy E1 and momentum p1, and photon #2 has energy E2 and momentum p2. What is p1 + p2? Then use that to show how E1 relates to E2.
 
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