Really Quick Differential Equation question

Saladsamurai
Messages
3,009
Reaction score
7
!Really Quick Differential Equation question...

Homework Statement


Alright so this is what I have for this problem. As you can see I used -i to find my Eigenvectors...now when I find my solution and plug it back into the original, I am getting the opposite of what I am supposed to get.

Was I supposed to use -t instead of +t in my solution since I used lambda=-i to find it?
Or did I make some stupid algebraic error again?


Picture3-4.png


THanks!
 
Physics news on Phys.org
I am thinking I should have used cos(-t) and sin(-t) since I used -i\Rightarrow \alpha=0\ \beta=-1
 
Saladsamurai said:
I am thinking I should have used cos(-t) and sin(-t) since I used -i\Rightarrow \alpha=0\ \beta=-1

I replaced t with -t and this worked. So I will assume my reason was correct.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top