Rearranging a Relativity Equation

  • Thread starter Thread starter TFM
  • Start date Start date
  • Tags Tags
    Relativity
TFM
Messages
1,016
Reaction score
0
[SOLVED] Rearranging a Relativity Equation

Homework Statement



Rewrite equation:

[tex]f = \sqrt{\frac{c + u}{c - u}}f_0[/tex]

to find the relative velocity u between the electromagnetic source and an observer in terms of the ratio of the observed frequency and the source frequency of light.

What relative velocity will produce a 3.0 decrease in frequency and

Homework Equations



Rearangement of:

[tex]f = \sqrt{\frac{c + u}{c - u}}f_0[/tex]

The Attempt at a Solution



I seem to get stuck when trying to rearrange the equation:

[tex]f = \sqrt{\frac{c + u}{c - u}}f_0[/tex]

[tex]\frac{f}{f_0} = \sqrt{\frac{c + u}{c - u}}[/tex]

[tex](\frac{f}{f_0})^2 = \frac{c + u}{c - u}[/tex]

[tex](c - u)(\frac{f}{f_0})^2 = c + u[/tex]

But I am not sure where to go from here.

Any suggestions?

TFM
 
on Phys.org
TFM said:
[tex](c - u)(\frac{f}{f_0})^2 = c + u[/tex]
You're doing fine; don't stop now.

[tex]c(\frac{f}{f_0})^2 - u(\frac{f}{f_0})^2 = c + u[/tex]

Next: Move all the terms containing u to one side.
 
Would that give:

[tex]c(\frac{f}{f_0})^2 - c = u(\frac{f}{f_0})^2 + u[/tex]

TFM
 
Do uou now factor out the u:

[tex]c(\frac{f}{f_0})^2 = u ((\frac{f}{f_0})^2 + 1)[/tex]

Tnhe divide over to get:

[tex]u = \frac{c(\frac{f}{f_0})^2 - c}{(\frac{f}{f_0})^2 + 1}[/tex]

Does this look right?

TFM
 
Looks good! (I would factor out the c to make it more readable.)
 
That would give:

[tex]u = \frac c((\frac{f}{f_0})^2) - 1}{(\frac{f}{f_0})^2 + 1}[/tex]


What relative velocity u will produce a 3.0 % decrease in frequency

For the actual question, do I put f_0 as 1 and f as 0.97?

TFM
 
TFM said:
That would give:

[tex]u = \frac c((\frac{f}{f_0})^2) - 1}{(\frac{f}{f_0})^2 + 1}[/tex]
:confused: Redo this. (Probably a formatting error.)
 
That definitely isn't right :

[tex]u = \frac{c((\frac{f}{f_0})^2 - 1)}{(\frac{f}{f_0})^2 + 1}[/tex]

TFM
 
Looks good.
 
  • #10
The actual question itself is:

What relative velocity u will produce a 3.0 % decrease in frequency

For this, should I put f_0 as 1 and f as 0.97?

TFM
 
  • #11
TFM said:
For this, should I put f_0 as 1 and f as 0.97?
Makes sense to me.
 
  • #12
It gives, the right answer, Thanks

One last thing, what is the question actually asking to find:

What relative velocity u will produce an increase by a factor of 3 of the observed light?

Does it want the freuqncy to be incresed by three factors?

TFM
 
  • #13
I'm no more a mind reader than you are! :smile: But since the problem seems to be talking about frequency and Doppler shifts, I would assume they mean that the observed frequency is three times the original.
 
  • #14
I calculated it to be 0.8, which is the answer, so I should say it is, as well.

Thats the second poorly worded question I've had this week:rolleyes:

Thanks for all the help,

TFM
 

Similar threads

Replies
17
Views
4K
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 39 ·
2
Replies
39
Views
4K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K