Recirculation Current in an Inductor

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SUMMARY

The discussion focuses on deriving the differential equation for a simple inductive circuit consisting of an inductor (L), a resistor (R), and a diode (D). Using Kirchhoff's law, the equation is established as Vdiode = Vinductor + Vresistor, leading to the differential equation L*di/dt + i*R = n*VT*ln(i/Is+1). The equation is then reformulated into standard form, prompting a request for assistance in solving the expression within the square brackets. The conversation emphasizes the importance of ensuring all terms in the ordinary differential equation (ODE) are positive, reflecting the energy dynamics of the inductor.

PREREQUISITES
  • Understanding of Kirchhoff's laws
  • Familiarity with ordinary differential equations (ODEs)
  • Knowledge of diode characteristics and models
  • Experience with numerical methods for solving differential equations
NEXT STEPS
  • Research numerical methods for solving ODEs, specifically in the context of electrical circuits
  • Explore Taylor series expansions for approximating solutions to differential equations
  • Study the SPICE simulation tool for circuit analysis and diode modeling
  • Investigate the impact of inductor energy storage on circuit behavior
USEFUL FOR

Electrical engineers, circuit designers, and students studying inductive circuits and differential equations will benefit from this discussion.

EigenFunctions
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I am trying to derive an equation for a simple inductive circuit which is the serial connection of an inductor (L), a resistor (R) and a Diode (D). The initial condition is a current flowing (Izero). Using Kirchhoff's law, the basic equation is:

Vdiode=Vinductor+Vresistor

The inductor is L*di/dt, the resistor is i*R and a simple model for a diode is n*VT*ln(i/Is+1) where n, VT and Is are constants. So the differential equation becomes:

L*di/dt + i*R = n*VT*ln(i/Is+1)

Putting it in standard form:

di/dt + [i*R/L - (n*VT/L)*ln((i/Is)+1)] = 0

I don't know how to deal with the expression in the square brackets.

Any suggestions?

Thanks,
EigenFunctions

PS - the diode function comes from Idiode(v) = Is*(exp(v/(n*VT)-1) as used in spice. Later, I will sum in an additional term for a diodes ohmic resistance.
 

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Solve numerically the way Spice would. Also check your signs. Shouldn't all terms in your ODE be positive?
 
Inductor is energy source re: Recirculation Current in an Inductor

marcusl said:
Solve numerically the way Spice would. Also check your signs. Shouldn't all terms in your ODE be positive?

You are correct, since the energy is stored in the inductor, it should be (see the updated attachment):

Vinductor = Vdiode + Vresistor

It seems like there should be a way to solve it, maybe with a Taylor series or something like that.

Thanks,
EigenFunctions
 

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