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Recognizing geometric series

  1. Nov 11, 2009 #1
    What is the algebra required to rewrite the nth term of: (sum from n=0 to infinity) of (pi^n)/(3^n+1) in geometric form?
     
  2. jcsd
  3. Nov 11, 2009 #2

    tiny-tim

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    Welcome to PF!

    Hi ollybabar! Welcome to PF! :smile:

    (have a pi: π and an infinity: ∞ and try using the X2 tag just above the Reply box :wink:)
    I don't understand your question …

    what do you mean by "geometric form"? and so you mean the sum of the first n terms? :confused:

    Anyway, it'll help if you rewrite it: (1/3) ∑ (π/3)n :wink:
     
  4. Nov 11, 2009 #3
    I've figured it out; thanks for the reply though.
     
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