Recovering Forces from Christoffel Symbols: A Derivation

In summary: Overall, your explanation provides a good starting point for understanding the connection between Christoffel symbols and forces.
  • #1
pervect
Staff Emeritus
Science Advisor
Insights Author
10,302
1,472
I don't think I've ever seen this discussed in a textbook, this is an attempt to throw some light on the connection between Christoffel symbols and forces.

In particular I want to derive the later as an approximation of the former, with some limitations on choices of coordinate systems (inertial frames).

I'll start off with assuming a cartesian coordinate system (t,x,y,z).
Next, we will add some "flatness" assumptions. Basically, to reduce the rank 3 Christoffel symbols to a rank 1 vector, we need the majority of them to be zero, or at least "small".

[itex]\Gamma^x{}_{tt}, \Gamma^y{}_{tt}, and \Gamma^z{}_{tt}[/tex] can be nonzero, the rest must be "small".

We will assume this to be the case, and check to see if it's sufficient for starters.

Now that we have the right rank, we still need to worry about the fact that Christoffel symbols aren't tensors. So we take a close look at the transformation law:

Wiki http://en.wikipedia.org/w/index.php?title=Christoffel_symbols&oldid=551829920

writes this as:

[tex]\overline{\Gamma^k{}_{ij}} =
\frac{\partial x^p}{\partial y^i}\,
\frac{\partial x^q}{\partial y^j}\,
\Gamma^r{}_{pq}\,
\frac{\partial y^k}{\partial x^r}
+
\frac{\partial y^k}{\partial x^m}\,
\frac{\partial^2 x^m}{\partial y^i \partial y^j} [/tex]

We can substitute in [itex]\partial y^i = \partial y^j = \partial t[/itex], since i and j must be equal to the index of t (usually zero) by our assumption.

[tex]\overline{\Gamma^k{}_{ij}} =
\frac{\partial x^p}{\partial t}\,
\frac{\partial x^q}{\partial t}\,
\Gamma^r{}_{pq}\,
\frac{\partial y^k}{\partial x^r}
+
\frac{\partial y^k}{\partial x^m}\,
\frac{\partial^2 x^m}{\partial t^2} [/tex]

We see that we need [itex] \frac{\partial^2 x^m}{\partial t^2} [/itex] to be zero - this is true if we transform between inertial frames.

This then leaves us with basically the basic tensor transformation law, except that forces transform quadratically with time.

This is a bit troublesome, apparently we can't do arbitrary time transformations t->t' if we wish to use forces. This makes sense, though, intiutively - it means as part of choosing an "inertial frame" we're stucking with choosing a regularly ticking clock if we wish to use forces. Then this factor becomes a simple scale factor.

I think that's pretty much the basics, though due to the limitations on time transformation, some extra attention should be paid to Lorentz transforms to demonstrate why four-fources work relativistically.

I feel there are some things lacking in this approach - it doesn't quite demonstrate that Lorentz transforms work, nor does it demonstrate, really, why you can use forces in polar coordinates. But I think it's a start.

If anyone has seen anything similar to this in the literature, I'd be interested in hearing about it.
 
Physics news on Phys.org
  • #2
This is an interesting approach to the connection between Christoffel symbols and forces. I appreciate that you have gone into detail about the assumptions and transformations needed to derive the later from the former. It makes sense that we need to choose a regularly ticking clock and a specific type of coordinate system in order to use forces.
I haven't seen anything similar to this discussed in textbooks, but I would be interested to know if anyone else has encountered this.
 

Related to Recovering Forces from Christoffel Symbols: A Derivation

1. What are Christoffel symbols?

Christoffel symbols are mathematical quantities used in the study of differential geometry and general relativity. They represent the components of a metric connection, which is a way of measuring distances on curved spaces.

2. Why is it important to recover forces from Christoffel symbols?

Recovering forces from Christoffel symbols allows us to understand the effects of gravity on objects in curved spaces. This is crucial in the field of general relativity, where gravity is described as the curvature of spacetime.

3. How is the derivation of recovering forces from Christoffel symbols done?

The derivation involves using the equations of motion and the definition of the Christoffel symbols to express the forces in terms of the metric tensor. Then, by substituting the metric tensor with its components in a particular coordinate system, the forces can be expressed in terms of Christoffel symbols.

4. What are the applications of recovering forces from Christoffel symbols?

Aside from its use in general relativity, this derivation has practical applications in fields such as aerospace engineering, where understanding the forces acting on objects in curved spaces is important for designing spacecraft trajectories.

5. Are there any limitations to this derivation?

The derivation assumes that the spacetime is described by a metric tensor, which may not always be the case. Additionally, it only applies to objects moving in a gravitational field, and does not take into account other forces such as electromagnetic or nuclear forces.

Similar threads

  • Special and General Relativity
Replies
11
Views
1K
  • Special and General Relativity
Replies
4
Views
3K
  • Special and General Relativity
Replies
3
Views
738
  • Special and General Relativity
Replies
19
Views
3K
  • Special and General Relativity
Replies
6
Views
5K
  • Special and General Relativity
Replies
2
Views
870
  • Special and General Relativity
Replies
4
Views
1K
  • Special and General Relativity
Replies
15
Views
1K
  • Special and General Relativity
Replies
7
Views
2K
  • Special and General Relativity
Replies
8
Views
1K
Back
Top