Redrawing a Circuit: Tips & Tricks for Power Sources

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SUMMARY

This discussion focuses on redrawing a circuit involving power sources and resistors, specifically addressing confusion around series and parallel configurations. The participants clarify the behavior of voltages, such as the -8V source, and how it affects current calculations. Key calculations include I1 = 6A from a 24V source across a 4Ω resistor, I2 = 16A from a combined voltage of 32V, and I3 = 0.8A from an 8V source across a 10Ω resistor. The importance of ground as a reference point for voltage measurements is also emphasized.

PREREQUISITES
  • Understanding of Ohm's Law (V=IR)
  • Familiarity with series and parallel circuits
  • Basic knowledge of node analysis in electrical circuits
  • Concept of voltage sources and their effects on current
NEXT STEPS
  • Study node analysis techniques for circuit simplification
  • Learn about Thevenin's theorem and its applications
  • Explore the impact of ideal voltage sources on circuit behavior
  • Review the principles of series and parallel resistor combinations
USEFUL FOR

Electrical engineering students, circuit designers, and anyone seeking to deepen their understanding of circuit analysis and power source interactions.

Magnawolf
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Homework Statement



aWALk5P.jpg


Homework Equations



I just need help redrawing the circuit

The Attempt at a Solution



I don't understand how to draw the power sources in correctly. I'm getting mixed on on whether they're in series or parallel with the resistors and such. Any tips would be appreciated.
 
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What's the point? There are no load nodes indicated, so I can't see that you are trying for a Thevenin equivalent and there is nothing wrong with the way the circuit is drawn now. What is it you are trying to do?

Edit: by the way, if you can't determine the current I1, you really need to go back and study the basics some more. There just is no way to create a more simple example of when to use V=IR
 
phinds said:
What's the point? There are no load nodes indicated, so I can't see that you are trying for a Thevenin equivalent and there is nothing wrong with the way the circuit is drawn now. What is it you are trying to do?

Edit: by the way, if you can't determine the current I1, you really need to go back and study the basics some more. There just is no way to create a more simple example of when to use V=IR
I'm trying to study the basics right now lol.

I understand I1 = 6, because the voltage is 24 V and the resistor is 4.

What throws me off is the -8V on the other side. How does it behave in the circuit?

I2 is apparently 16A. Is it because the voltage through the resistor is 32V?

Now what confuses me is I3. I3 is apparently 0.8A, which is 8V/10Ω. Does that mean the 24V has no effect on that resistor? If so, why? Does the ground play a role in this circuit?

Also, I is 22V which I don't understand at all. I'm assuming I have to find R-total and E-net. Are all the resistors in parallel? That -8V is throwing me off. Would E-net be 24+8 = 32V?
 
Magnawolf said:
I'm trying to study the basics right now lol.

I understand I1 = 6, because the voltage is 24 V and the resistor is 4.

good.

What throws me off is the -8V on the other side. How does it behave in the circuit?

I2 is apparently 16A. Is it because the voltage through the resistor is 32V?
. Yes, 24 minus a minus 8 adds up to 32.

Now what confuses me is I3. I3 is apparently 0.8A, which is 8V/10Ω. Does that mean the 24V has no effect on that resistor? If so, why?
How could it be anything else? It has an ideal voltage source across it that is 8v. That makes it irrelevant what the rest of the circuit is doing.

Does the ground play a role in this circuit?

It gives you a reference point for ALL of the voltages in the circuit.

Also, I is 22V which I don't understand at all. I'm assuming I have to find R-total and E-net. Are all the resistors in parallel? That -8V is throwing me off. Would E-net be 24+8 = 32V?

Forget the voltage. You've already FOUND all of the currents in that node except for I, so just do a simple node analysis. 16+6=22.
 
thanks bruh
 

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