Reduction formula (sinx)^n inequality

kenok1216
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Homework Statement


problem 4.PNG

part c

Homework Equations



The Attempt at a Solution


Jm+2=m+2-1/m+2 Jm=m+1/m+2 Jm
hence Jm+2<Jm
should i expend Jm+2 Jm+1 Jm to the term J0 then compare them?
why the inequality is <= but not <?
should i use M.I to proof it??[/B]
 
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kenok1216 said:

Homework Statement


View attachment 102041
part c

Homework Equations



The Attempt at a Solution


Jm+2=m+2-1/m+2 Jm=m+1/m+2 Jm
hence Jm+2<Jm
should i expend Jm+2 Jm+1 Jm to the term J0 then compare them?
why the inequality is <= but not <?
should i use M.I to proof it??[/B]

Please stop using a bold font; it looks like you are yelling at us.

Anyway, what does your formula
J_{m+2} = m+2 - \frac{1}{m} + 2J_m = m + \frac{1}{m} + 2J_m
mean, and where does it come from? Is what you wrote exactly what you meant? Do you need to use parentheses to make your expression clearer?
 
Use the basic property of integrals that if f(x) \geq g(x) for all x \in (a,b) then \int_a^b f(x)\,dx \geq \int_a^b g(x)\,dx.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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