Reference Frames: Up and Down a River

AI Thread Summary
The discussion focuses on the motion of a water spider navigating a stream by darting upstream and drifting downstream. The current of the stream is 0.408 m/s, and the spider moves 0.558 m upstream in 0.844 seconds. Calculations reveal the spider's velocity relative to the water during its upstream dash is approximately 0.253 m/s, while its downstream drift velocity is about 1.069 m/s. The total distance moved upstream relative to the water during one cycle is discussed, and the average velocity for the complete cycle is calculated. Participants emphasize the importance of understanding the terms "darting" and "drifting" in the context of the problem.
TheDestroyer123
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Homework Statement



A water spider maintains an average position on the surface of a stream by darting upstream (against the current), then drifting downstream (with the current) to its original position. The current in the stream is 0.408 m/s relative to the shore, and the water spider darts upstream 0.558 m (relative to a spot on shore) in 0.844 s during the first part of its motion. Use upstream as the positive direction.

a) Find the velocity of the water spider relative to the water during its dash upstream.
Answer in units of m/s

b) What is its velocity (relative to the water) during its drift downstream?
Answer in units of m/s

c) How far upstream relative to the water does the water spider move during one cycle of this upstream and downstream motion?
Answer in units of m

d) What is the average velocity of the water spider relative to the water for one complete cycle?
Answer in units of m/s

Homework Equations



-None-

The Attempt at a Solution



I believe I am doing this right, but when I submit my answers online, the website says they are all (a-d) wrong. Am I doing something wrong?

V(of spider relative to ground)=.558m/.844s = .6611

a) V(of spider relative to water)= V(of spider relative to ground) -V(of ground relative to water)
VSW=VSG-VGW
VSW=.6611-.408=.2531 m/s

b) VSW=VSG-(-VGW)
VSW=.6611+.408=1.0691 m/s

c)DSW=(VSW)t
DSW=(.2532)(.408)=.2336 m

d) AverageSW= (.2531+1.0691)/2 = .6611 m/s
 
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TheDestroyer123 said:

Homework Statement



A water spider maintains an average position on the surface of a stream by darting upstream (against the current), then drifting downstream (with the current) to its original position. The current in the stream is 0.408 m/s relative to the shore, and the water spider darts upstream 0.558 m (relative to a spot on shore) in 0.844 s during the first part of its motion. Use upstream as the positive direction.

a) Find the velocity of the water spider relative to the water during its dash upstream.
Answer in units of m/s

b) What is its velocity (relative to the water) during its drift downstream?
Answer in units of m/s

c) How far upstream relative to the water does the water spider move during one cycle of this upstream and downstream motion?
Answer in units of m

d) What is the average velocity of the water spider relative to the water for one complete cycle?
Answer in units of m/s

Homework Equations



-None-

The Attempt at a Solution



I believe I am doing this right, but when I submit my answers online, the website says they are all (a-d) wrong. Am I doing something wrong?

V(of spider relative to ground)=.558m/.844s = .6611

a) V(of spider relative to water)= V(of spider relative to ground) -V(of ground relative to water)
VSW=VSG-VGW
VSW=.6611-.408=.2531 m/s
The spider moves upstream while the water flows downstream. If the velocity f the spider is positive, that of the water is negative.
You have never tried to swim upstream? you have to swim hard just to stay at the same place with respect to the ground...

TheDestroyer123 said:
b) VSW=VSG-(-VGW)
VSW=.6611+.408=1.0691 m/s

Read the question carefully:
b) What is its velocity (relative to the water) during its drift downstream?

What does drift mean ?
It is explained in the first sentence of the problem:
drifting downstream (with the current)
 
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