 #1
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In Figure 3348a, a light ray in a liquid (n = 1.61) is incident at angle 1 on a boundary with an underlying material, into which some of the light refracts. There are two choices of underlying material. For each, the angle of refraction 2 versus the incident angle 1 is given in Figure 3348b. Without calculation, note whether the indices of refraction of material 1 and material 2 are greater or less than the index of the liquid.
What is the index of refraction of material 1?
What is the index of refraction of material 2?
I understand that you use snells law,
and
Material #1:
Incident Angle = 67.5 deg
Refraction Angle = 56.25 deg
→ n1 = nwater*Sin(Incid Ang)/Sin(Refr Ang)
= (1.61)*Sin(67.5 deg)/Sin(56.25 deg)
= 1.79
which isn't correct
What is the index of refraction of material 1?
What is the index of refraction of material 2?
I understand that you use snells law,
and
Material #1:
Incident Angle = 67.5 deg
Refraction Angle = 56.25 deg
→ n1 = nwater*Sin(Incid Ang)/Sin(Refr Ang)
= (1.61)*Sin(67.5 deg)/Sin(56.25 deg)
= 1.79
which isn't correct
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