Refraction Problem- very easy but

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The discussion addresses a refraction problem involving the calculation of angles between liquid and air. Participants clarify that the angle of refraction into air is 90 degrees, not 180 degrees, and emphasize the importance of correctly identifying angles in the equations. There is a mention of the refractive index of air being 1, which is crucial for solving the problem. Additionally, there are side comments about forum etiquette, particularly regarding the deletion of posts after receiving help. The conversation highlights the need for clear communication and adherence to community guidelines to ensure effective assistance.
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[SOLVED] Refraction Problem- very easy but need help

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Where is 180 deg coming from? What is the angle of refraction from liquid to air? What is the corresponding angle in the liquid?
 
The eqn is right.
 
physicsbhelp said:
so would the corresponding angle be

sin(theda)N1=sin(theda2)N2

so that means that theda2=180 so that part of the equation = 0. so sin(theda1)1.85?

Look at theta2, by which I presume you mean the angle of refraction into air. Does it look like 180 deg?
 
Yes, "theda2" would be 90 deg.
 
You're almost there. Check your thedas, which one goes where.

(Here again, sin theda1 > 1.)
 
Yes and N2=1. (RI of air.)
 
THANK YOU SO MUCH FOR YOUR HELP SHOOTING STAR! you are the BEST!
 
  • #10
what am I? chopped liver?
 
  • #11
Dear physicsbhelp,

The way you are deleting your own posts I find hilarious, though I don't know why you are doing it. I must share this with others. Hope you don't mind.
 
  • #12
physicsbhelp said:
. . . .
Stop playing these games (deleting your posts after getting help) or you will soon find yourself unable to get any help.

To the helpers: Please report this kind of activity.
 

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