rocomath
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Refresh my memory please, Inverse Trig
x=\sin^{-1}\left(-\frac{\sqrt{2}}{2}\right)
Inverse sine is defined from -\frac{\pi}{2} to \frac{\pi}{2} which lies in the 1st and 4th quadrant.
So x=-\frac{\pi}{4}
x=\sin^{-1}\left(-\frac{\sqrt{2}}{2}\right)
Inverse sine is defined from -\frac{\pi}{2} to \frac{\pi}{2} which lies in the 1st and 4th quadrant.
So x=-\frac{\pi}{4}