Refresh my memory , Inverse Trig

AI Thread Summary
The discussion focuses on the inverse sine function, specifically calculating x = sin^(-1)(-√2/2), which equals -π/4 or approximately -0.785 radians. Participants clarify that the inverse sine is defined between -π/2 and π/2, covering the first and fourth quadrants. There is confusion regarding calculator outputs, with one user mistakenly believing they receive different results for sin and arcsin calculations. The correct understanding is that sin(-π/4) yields -√2/2, aligning with the arcsine result. The conversation emphasizes that the outputs for sin and arcsin will not match in magnitude, reinforcing the properties of inverse trigonometric functions.
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Refresh my memory please, Inverse Trig

x=\sin^{-1}\left(-\frac{\sqrt{2}}{2}\right)

Inverse sine is defined from -\frac{\pi}{2} to \frac{\pi}{2} which lies in the 1st and 4th quadrant.

So x=-\frac{\pi}{4}
 
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rocomath said:
x=\sin^{-1}\left(-\frac{\sqrt{2}}{2}\right)

Inverse sine is defined from -\frac{\pi}{2} to \frac{\pi}{2} which lies in the 1st and 4th quadrant.

So x=-\frac{\pi}{4}

Correct -- and your calculator and mine will back you up on that...
 
dynamicsolo said:
Correct -- and your calculator and mine will back you up on that...
That's the thing, it gives me different answers. (in radians)

\sin^{-1}\left(-\frac{1}{\sqrt 2}\right)\approx -0.785

\sin\left(-\frac{\pi}{4}\right)\approx -0.707
 
Those aren't different answers. -pi / 4 is -0.785 and -1/ root 2 is -0.707.

The inverse sin of the ratio will give you the angle, the sin of the angle will give you the ratio.
 
rocomath said:
That's the thing, it gives me different answers. (in radians)

\sin^{-1}\left(-\frac{1}{\sqrt 2}\right)\approx -0.785

\sin\left(-\frac{\pi}{4}\right)\approx -0.707

And -45º converted to radians is? (In other words, what's \frac{-\pi}{4}?)

[I expect we're going to hear a "D'oh!" in 3, 2, 1, ...]
 
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dynamicsolo said:
And -45º converted to radians is? (In other words, what's \frac{-\pi}{4}?)

[I expect we're going to hear a "D'oh!" in 3, 2, 1, ...]
LOL, I know that ... but what's with the calculator? Am I putting it in right?
 
rocomath said:
LOL, I know that ... but what's with the calculator? Am I putting it in right?

Of course you are! The sine of -45º or -pi/4 radians (which is approximately -0.785398... radians) gives you -1/sqrt(2) =
-[sqrt(2)]/2 = -0.70710678... ,
so taking the arcsine of (-0.70710678...) should give you
-0.785398...

I guess we're puzzled why you're puzzled. There's no reason you should get the same number in both directions. The magnitude of arcsin(x) doesn't match the magnitude of sin(x) at x = (pi)/4 ...
 
LMAO ... omg, I crack myself up :)
 
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