The inside of an ideal refrigerator is at a temperature , while the heating coils on the back of the refrigerator are at a temperature . Owing to a malfunctioning switch, the light bulb within the refrigerator remains on when the the door is closed. The power of the light bulb is ; assume that all of the energy generated by the light bulb goes into heating the inside of the refrigerator. For all parts of this problem, you must assume that the refrigerator operates as an ideal Carnot engine in reverse between the respective temperatures. If the temperatures inside and outside of the refrigerator do not change, how much extra power does the refrigerator consume as a result of the malfunction of the switch? (Express the extra power in terms of P,T_h,and T_c) i know that Q/W_in = Tc/T_h-T_c and W_out/Q_H = 1-T_c/T_h i'm just not sure how to equat this to power... would the W_in be the power of the light bulb? i get something like 1-(P(T_c/T_h-T_c) but that can't be right... if someone could help, that would be great!