Related Rates + HOw to find a variable

madeeeeee
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Gravel is being dumped from a conveyor belt at a rate of 30 ft3/min and its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal. How fast is the height of the pile increasing when the pile is 10 ft high?

Known:
dV/dt=30 ft^3/min
Cone Volume= 1/3(pi)(r^2)(h)

Unkown:
dh/dt= ? when h= 10ft

I am confused about how to find the height and radius of the pile if they are equal.
height=radius

Please help me with this thank you and i am sure that i will be able to solve this problem.
Thank you
 
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Use the relationship between height and radius to eliminate the radius from the volume relationship. Now you can find dV/dt and the required answer.
 
ok thank you

Also, if i have the function y=x^3-3x^2
is my horizontal asymptote 1?
 
madeeeeee said:
ok thank you

Also, if i have the function y=x^3-3x^2
is my horizontal asymptote 1?
?
This function does not have a horizontal asymptote. Did you mean x-intercepts? If so, there are two: x = 0 and x = 3.
 
ok, so does that mean that there is also no, vertical or slant asymptote?
 
y = x^3 - 3x^2 doesn't have any asymptotes at all.
 
ok thank you
 

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