Relating change in time to change in position and velocity

AI Thread Summary
The discussion centers on the equation Δt = 2*Δx/(vf+vi) and its validity for calculating time change (Δt). The user initially questions the origin of this equation but later realizes it is derived from the rearrangement of the formula d = (vf+vi)/2 * t. This highlights the relationship between displacement, average velocity, and time in motion equations. The equation is confirmed as a valid method for finding Δt, emphasizing its utility in solving problems involving constant acceleration. Understanding this relationship is crucial for mastering motion concepts in physics.
OneObstacle
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I was looking back at some homework solutions I've solved earlier this term and I ran across this equation:

Δt = 2*Δx/(vf+vi)

Which seems to translate to:

Δt = Δx/vave

Is this an actual way of finding delta t? I got the answer right, but I can not understand or find where I got this equation.

EDIT: Can someone take this down? I found out I just rearranged d = (vf+vi)/2 * t
 
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OneObstacle said:
I was looking back at some homework solutions I've solved earlier this term and I ran across this equation:

Δt = 2*Δx/(vf+vi)

Which seems to translate to:

Δt = Δx/vave

Is this an actual way of finding delta t? I got the answer right, but I can not understand or find where I got this equation.

EDIT: Can someone take this down? I found out I just rearranged d = (vf+vi)/2 * t

Yes, correct, d = vavet seems to be one of the most forgotten but helpful of the 5 motion equations for constant acceleration.
 

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