Relating charge to potential difference

AI Thread Summary
To determine the potential difference needed for singly ionized 12C atoms to achieve a semicircular path of radius 50 cm in a 0.15T magnetic field, the relevant equations involve the relationship between velocity, charge, mass, and magnetic field. The participant is struggling to find a way to equate the provided data without knowing the charge or linear velocity of the ions. The discussion highlights the importance of understanding the term "singly ionized," which indicates that the ions have lost one electron, thus having a charge of +1e. Clarification on this term has helped the participant feel more confident in proceeding with the calculations. The conversation emphasizes the need for a clear understanding of the physics concepts involved in the problem.
Daishain
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Homework Statement


Ions with mass m and charge q are accelerated through a potential difference V. They then enter a uniform magnetic field perpendicular to their velocity and are deflected in a semicircular path of radius R

What potential difference V is needed so that singly ionized 12C atoms will have R= 50 cm in a 0.15T magnetic field?

radius R= 50 cm
magnetic field strength B= 0.15 T
mass m= 1.993 X10^-26 kg
charge q=?
linear velocity v=?
voltage difference V=?

Homework Equations


v=(R*|q|*B)/m
V=(0.5*m*v^2)/q

Not looking for a specific solution from here. I need a new way to equate the data. No matter how I slice it given the formulas and data provided, I cannot find the potential difference without either the particle's charge or its linear velocity.
 
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Daishain said:

Homework Statement


Ions with mass m and charge q are accelerated through a potential difference V. They then enter a uniform magnetic field perpendicular to their velocity and are deflected in a semicircular path of radius R

What potential difference V is needed so that singly ionized 12C atoms will have R= 50 cm in a 0.15T magnetic field?

radius R= 50 cm
magnetic field strength B= 0.15 T
mass m= 1.993 X10^-26 kg
charge q=?
linear velocity v=?
voltage difference V=?

Homework Equations


v=(R*|q|*B)/m
V=(0.5*m*v^2)/q

Not looking for a specific solution from here. I need a new way to equate the data. No matter how I slice it given the formulas and data provided, I cannot find the potential difference without either the particle's charge or its linear velocity.

What do you suppose the phrase "singly ionized" implies?
 
gneill said:
What do you suppose the phrase "singly ionized" implies?

*facepalm*

I had assumed it meant nothing more than that ions were produced and released in series. Thanks for pointing it out, I should be able to handle it from here.
 
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