Relating increament of speed to time

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SUMMARY

Aditya's bicycle journey from town P to town Q can be analyzed using the formula for speed, where speed (s) equals distance (d) divided by time (t). If Aditya increases his speed by 3 m/s, he arrives at town Q three times faster, indicating that his new speed is effectively three times his original speed. Therefore, if he increases his speed by 6 m/s, he will arrive at town Q six times faster than his original speed.

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Aditya rides a bicycle from town P to town Q with a constant speed. If he increases his speed by 3 m/s, he will arrive to town Q three times faster. How many times faster will Aditya arrive to town Q, if he increases his speed by 6 m/s



s=\frac{d}{t}



Let his constant speed be x
x= d/t
Therefore x+3 = (d/t) +3
_____________________________________

C'est tout! What next?
 
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Hi MoniMini! :smile:
MoniMini said:
Let his constant speed be x
x= d/t
Therefore x+3 = (d/t) +3

ok so far!

now translate "he will arrive to town Q three times faster" :wink:
 
tiny-tim said:
Hi MoniMini! :smile:


ok so far!

now translate "he will arrive to town Q three times faster" :wink:

Umm...That's the problem...I'm not being able to do that :(
 
if the new speed, x+3, is 3 times faster,

that means it must be 3x :wink:
 

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