The projection of Y orthogonal to X can be expressed as (a scalar multiple of)
$$Y' = Y - \frac{\langle X, Y\rangle X }{ \langle X, X \rangle} ,$$
wherever ## \langle X, X \rangle\neq 0##. We can define the flow curves via ##\dot{\gamma}_Y(t) = Y \gamma(t)## and ##\dot{\gamma}_{Y'}(t) = Y' \gamma(t)##. In principle we can use the same parameter ##t## to describe both of these curves, but the curve for ##Y'## will also depend on the vector field ##X##, so I don't think there's a general answer to your question. If ##X## and ##Y## are given and nice enough, then we can just solve for the curves to work out the relationship.