Relation between Potential Field, Force, Kinetic Energy and Abs.Energy

AI Thread Summary
The discussion clarifies the relationship between work, potential energy, and kinetic energy in conservative force systems. It establishes that work done (W) corresponds to the change in energy (ΔE), expressed as W = ∫xixf F dx = ΔE. The force is defined as the negative gradient of potential energy (F = -∇U), leading to the conclusion that the change in potential energy (ΔU) equals the negative work done (ΔU = -W). A key point is distinguishing between work done by conservative forces and work done against them when lifting objects. Understanding these relationships is crucial for grasping energy conservation principles in physics.
EEristavi
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Homework Statement
A single conservative force acts on a 5.00-kg particle
within a system due to its interaction with the rest of the
system. The equation Fx = 2x + 4 describes the force,
where Fx is in newtons and x is in meters. As the particle
moves along the x axis from x = 1.00 m to x = 5.00 m,
calculate (a) the work done by this force on the particle,
(b) the change in the potential energy of the system, and
(c) the kinetic energy the particle has at x 5 5.00 m if its
speed is 3.00 m/s at x 5 1.00 m.
Relevant Equations
W = ∫ F dx
F = -∇U
I understand that the work done is Change of Energy.
W = ∫xixf F dx = ΔEThe force is gradient of potential energy
F = -∇U (For conservative forces of course)

from here, we can say that change of potential energy is W:
ΔU = -W
but also
ΔU = -W = ΔE

I'm little bit lost here..
Can you help me understand this topic? where I make mistake?
 
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EEristavi said:
from here, we can say that change of potential energy is W:
ΔU = -W
Don't confuse the work done on the object by the conservative force with the work you need to do against the conservative force to lift the object.
 
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