Relation of resistance to power dissipation

AI Thread Summary
The discussion centers on the relationship between resistance and power dissipation in resistors, highlighting an apparent paradox between two equations: p = i^2 * R and p = v^2 / R. When resistance decreases, current increases according to Ohm's law, which affects power dissipation. Specifically, reducing resistance by half doubles the current, leading to a fourfold increase in power dissipation using the first equation. The second equation confirms this by showing that power changes inversely with resistance. Ultimately, both equations align when considering the constant voltage scenario, clarifying the relationship between resistance, current, and power dissipation.
omari_yousef
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Equation (p=i^2 * R) seems to suggest that the rate of increase of thermal energy in a resistor is reduced if the resistance is made less.

"Eq" : p =v^2/R seems to suggest just the apposite .

How do you reconcile this apparent paradox?
 
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omari_yousef said:
Equation (p=i^2 * R) seems to suggest that the rate of increase of thermal energy in a resistor is reduced if the resistance is made less.

"Eq" : p =v^2/R seems to suggest just the apposite .

How do you reconcile this apparent paradox?

You reconcile it by noticing that, if V is constant, then you cannot reduce R without increasing I (ohm's law). If you reduce R by a factor of 2, then you increase I by a factor of 2, which means that, using the first equation, your power changes by a factor of (2^2)/2 = 4/2 = 2.

Using the second equation, your power changes by a factor of 1/(1/2) = 2.
 
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