Relationship between Debye Temperature and Speed of Sound in Metals

AI Thread Summary
The discussion focuses on understanding the relationship between Debye temperature and the speed of sound in metals, specifically through an example involving Silicon and Lead. The Debye temperature is calculated using the equation Θ_D = ℏω_D / k_B, where ω_D is related to the speed of sound. The process involves finding the cutoff frequency using the linear dispersion relation, with the relationship between frequency and wave vector being critical. Participants highlight the importance of estimating the unit cell dimension to simplify calculations. The conversation concludes with a successful resolution of the problem after clarifying the method to find the necessary parameters.
Hemmer
Messages
15
Reaction score
0

Homework Statement



I'm struggling to understand the relationship between the Debye temperature and the speed of sound in a substance. An example problem given is:

Estimate the Debye Temperature of Silicon and Lead, given that their respective speeds of sound are 9150 m/s and 1320 m/s. (not sure if its relevant to this part of the question but also given graph of C_v vs T for Argon from which you can read a Debye temp of about ~80K).


Homework Equations



\Theta_D = \hbar \omega_D / k_b
where \omega_D = c k_D
and k_D is the radius of the "Debye Sphere"

The Attempt at a Solution



Not sure how to attempt this to be honest, there seems like there are too many unknowns. Presumably there is some simplifying assumption, but I'm not sure where to begin...
 
Physics news on Phys.org
you first need to find the cut off frequency wd by using the linear dispersion relation. For the Debye model w is proportional to k. At the long wavelength limit k=pi/a where a is the dimension of the unit cell. Having found w you can then substitute it back into your first equation for temperature.
 
captainjack2000 said:
you first need to find the cut off frequency wd by using the linear dispersion relation. For the Debye model w is proportional to k. At the long wavelength limit k=pi/a where a is the dimension of the unit cell. Having found w you can then substitute it back into your first equation for temperature.

Thanks yes this makes sense. I had funnily enough just worked it out 5 mins ago, I forgot that k could be found fairly easily by estimating a.
 
Thread 'Help with Time-Independent Perturbation Theory "Good" States Proof'
(Disclaimer: this is not a HW question. I am self-studying, and this felt like the type of question I've seen in this forum. If there is somewhere better for me to share this doubt, please let me know and I'll transfer it right away.) I am currently reviewing Chapter 7 of Introduction to QM by Griffiths. I have been stuck for an hour or so trying to understand the last paragraph of this proof (pls check the attached file). It claims that we can express Ψ_{γ}(0) as a linear combination of...
Back
Top