- #1
ladybeetle
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I WOULD BE VERY THANKFUL IF ANYONE COULD PLEASE ME WITH THIS PROBLEM! :)
Particle 1 with mass m1 encouters elastic collision with particle 2 which has mass m2
Assume that particle 2 is stationary before collision.
And movement-direction of particle 1 after collision, is perpendicular to the movement-direction before collision.
Let T1 symbolize kinetic-energy of particle 1 before collision
And p'1 momentum of particle 1 after collision
a) show that the angle between the movement-direction of particle 2 after collision and movement-direction of particle 1 before collision if θ where
tanθ = lp'1l / sqrt(2T1m1+T1^2/c^2)
b)show that after collision, length of the momentum-vector of the particle 2 is
sqrt( lp'1l+2T1m1+T1^2/c^2)
Particle 1 with mass m1 encouters elastic collision with particle 2 which has mass m2
Assume that particle 2 is stationary before collision.
And movement-direction of particle 1 after collision, is perpendicular to the movement-direction before collision.
Let T1 symbolize kinetic-energy of particle 1 before collision
And p'1 momentum of particle 1 after collision
a) show that the angle between the movement-direction of particle 2 after collision and movement-direction of particle 1 before collision if θ where
tanθ = lp'1l / sqrt(2T1m1+T1^2/c^2)
b)show that after collision, length of the momentum-vector of the particle 2 is
sqrt( lp'1l+2T1m1+T1^2/c^2)
