Relativistic Notation in Waves: Confusion Solved

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 1K views
kent davidge
Messages
931
Reaction score
56
If we have a plane wave, usually in Relativity notation it is written as ##A^\alpha = a^\alpha \exp(i x_\alpha k^\alpha)##. (I know we need to take the real part in the end). In cartesian coordinates, and two dimensions say, that ##x_\alpha k^\alpha## would be ##x^\alpha k_\alpha = x k_x + y k_y##. How does it reads in polar coordinates? ##x^\alpha' k_\alpha' = r k_r + \theta k_\theta = r [(\partial x/ \partial r)k_x + (\partial y/ \partial r)k_y] + \theta [(\partial x/\partial \theta )k_x + (\partial y/\partial \theta )k_y] = r (\cos\theta k_x + \sin\theta k_y) + \theta[(-r\sin\theta ) k_x + (r\cos\theta ) k_y]##. The first term is just equal to its version in Cartesian coordinates. But then there is that second term, which makes ##x^\alpha' k_\alpha' \neq x^\alpha k_\alpha##. I already expected this result from the fact that ##x^\alpha## do not transform like, and thus are not, four vectors. So a product like ##x^\alpha k_\alpha## will not be a scalar.

But then what does this result mean? A field like ##A^\alpha = a^\alpha \exp(i x_\alpha k^\alpha)## will not transform as a vector if the exponent is not a scalar. But it should transform as a vector. So what we do?
 
Physics news on Phys.org
If you want to do non-Minkowski coordinates, then you should replace ##x^\alpha## by the event vector (which in Minkowski coordinates have the coordinates as components - just like the position vector in Cartesian coordinates in Euclidean space has the coordinates as components).
 
Orodruin said:
event vector
Sorry, I never heard about the event vector. What is it?
 
Orodruin said:
It is the same thing in Minkowski space as the position vector is in Euclidean space.
Ok. That makes a lot of sense.

- we know that in Minkowski coordinates the term has the form ##x^\alpha k_\alpha##;
- we also know that it should be a scalar;
- so we identify ##x^\alpha## as the components of a vector;

Do you know which symbol is used to denote this vector?