Relearning differential equations,

Daniel Sellers
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Homework Statement


I was never great in diffEQ, but now I have to solve this problem for physics homework and I'm pretty lost.

d^4x/dx^4 - d^2x/dx^2 + a =0

Where a is a parameter.

Homework Equations

The Attempt at a Solution


I have tried solutions like e^kt which work accept for the parameter a. The problem asks specifically what happens if a varies, so I can't even treat it like a constant
 
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Daniel Sellers said:

Homework Statement


I was never great in diffEQ, but now I have to solve this problem for physics homework and I'm pretty lost.

d^4x/dx^4 - d^2x/dx^2 + a =0

Where a is a parameter.

Homework Equations

The Attempt at a Solution


I have tried solutions like e^kt which work accept for the parameter a. The problem asks specifically what happens if a varies, so I can't even treat it like a constant

I assume you mean ##d^4 x/dt^4##, etc; otherwise your DE makes no sense at all!

I suspect they mean that ##a## is a "parameter" that is fixed throughout a solution, but that different values of ##a## can give you different solutions. At least, that is how I read it. Otherwise, the problem should have written ##a(t)## instead of just plain ##a##.

Anyway, if ##a## really is a constant, the function ##y = d^2 x/dt^2## satisfies ##d^2 y /dt^2 - y + a = 0##, so ##z = y-a## satisfies ##d^2 z /dt^2 - z = 0.##
 
Yes, there are t's in the denominator. Tha ks so much, I think that will work!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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