Removal of oxygen on Boron powders

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Methanol reacts with B2O3 to form boron esters that volatilize upon evaporation, a process linked to enolate formation and breakdown. This reaction is discussed in organic chemistry texts, particularly in relation to the aldol reaction. For pressing and sintering powders, it is advised to seek alternative suppliers and maintain an argon atmosphere. Using a hot hydrogen stream may introduce complications due to hydrogen dissolution in boron. Wet methods are not recommended for this process.
woodyanderson
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Have read that methanol reacts with B2O3 to produce Boron esters which volatilize during evaporation. Does this work? If so how?:!)
 
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Looks like enolate formation and breakdown. You should find something about it in an organic chemistry text, under the aldol reaction. Can't say I know very much about it, but there may be some organic chemists here that can do better.
 
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If you're pressing and sintering powders, find another supplier and keep the stuff under argon. If you're messsing around with other uses, you can try a hot hydrogen stream --- you'll probably get enough H dissolved in the B to screw you up, though. Wet methods? Forget it.
 
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