Representing Vectors in 3D Space

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    3d Space Vectors
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In 3D space, a full vector can be represented in various forms, including Cartesian vector form, as a magnitude times a unit vector, and as a magnitude with coordinate angles. The discussion centers on identifying the incorrect representation among the options provided. The consensus leans toward option C, which suggests that a Cartesian vector times a unit vector may not be a valid representation. This is supported by the understanding that multiplying vectors typically results in a scalar when using the dot product. Clarification on the meaning of "times" in this context is crucial for determining the correct answer.
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Homework Statement



In 3D space a full vector can be represented I. All the following except
A. In Cartesian vector form
B.As a magnitude times a unit vector
C. As a Cartesian vector times a unit vector
D. As magnitude with coordinate angles

Homework Equations





The Attempt at a Solution


I say the answer is reason being I found all the other statements correct therefore I solve by elimination of variables. Any help would be g greatly appreciated and verification for my answer.
 
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Tiven white said:

Homework Statement



In 3D space a full vector can be represented I. All the following except
A. In Cartesian vector form
B.As a magnitude times a unit vector
C. As a Cartesian vector times a unit vector
D. As magnitude with coordinate angles

Homework Equations





The Attempt at a Solution


I say the answer is reason being I found all the other statements correct therefore I solve by elimination of variables. Any help would be g greatly appreciated and verification for my answer.

What does a vector times a vector mean? Think about that.
 
Dick said:
What does a vector times a vector mean? Think about that.


Is the answer c due to the fact that the vector times a vector can produce a scalar
 
Tiven white said:
Is the answer c due to the fact that the vector times a vector can produce a scalar

Depends on what the problem means by 'times'. If the only product you know about is the dot product, then yes, answer c is certainly a candidate for elimination.
 
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