Resistance of a brick - Old coursework question

AI Thread Summary
The discussion revolves around the challenges of measuring the electrical resistance of a household brick using standard school lab equipment. Participants highlight significant obstacles, including the high resistance of bricks compared to air, the difficulty of uniformly heating a brick to 600°C, and the need for extremely high voltages to pass current through the brick. Suggestions for alternative methods, such as using a Wheatstone bridge and specialized equipment like a Tesla coil or pico-ammeter, are mentioned, but these remain impractical in a school setting. The consensus is that the experiment, as designed, is nearly impossible to conduct effectively with available resources. Overall, the conversation emphasizes the limitations of school lab equipment for such advanced experiments.
Burningmace
Messages
14
Reaction score
0
Back when I was doing A-Level physics we were given a coursework assignment that seemed rather ridiculous, which I've been thinking about recently. We were charged with measuring the electrical resistance of a standard household brick at different temperatures, using only equipment we could find in a school lab. Our teacher thought it was insane, as did I. I got a second opinion from my father (he's an electronics engineer that works on diesel-electric locomotives), and he said the only way to do it realistically would be to use a Tesla coil, and that's not exactly something schools just keep in the store room. The solution they were looking for turned out to be a Wheatstone bridge, not that it'd ever work.

The obvious issues:
1) Bricks aren't solid and have higher resistance than air, so any current being passed through is more likely to arc round the brick through the air. Only solution - do the experiment in a vacuum.
2) Heating a brick to 600C uniformly in air isn't an easy task with lab equipment, let alone in a vacuum.
3) Generating the extremely high voltage required to pass a current through the brick is a big problem.
4) Measuring the resistance at such high voltages is practically impossible without special equipment.

I ended up writing that the experiment was impossible using lab equipment - the closest thing even vaguely plausible would be to use an EHT supply with a Wheatstone bridge, with a heat-resistant bell jar to heat the brick in a vacuum, then went on to describe experiments that were more likely to yield a result.

I know the electrical resistance of bricks has been measured before for lightning safety purposes, but these experiments would have used Tesla coils to generate extreme voltages.

Anyone think of something we missed?
 
Physics news on Phys.org
Well, EE technology has advanced a bit since the old locomotive days, so I'd suggest using a laboratory-quality DVM to do your measurements. And to do the measurements versus humidity (DI water chamber), and versus humidity (room air source chamber).

Plot those data and you will have your answers.
 
I think you misunderstood. We were meant to do this experiment with school level lab equipment. Furthermore the variable was heat, not humidity.
 
Burningmace said:
I think you misunderstood. We were meant to do this experiment with school level lab equipment. Furthermore the variable was heat, not humidity.

Fair enough. Have you calculated the expected results yet? Do you have numbers for the volume resistivity of the brick material? It would help to have a ballpark idea going into the experimental design what kind of numbers you will be measuring.

The most accurate high-resistivity measurements I've made were done using a "Pico-Ammeter". Do you have such an instrument in your lab equipment? It's a pretty specialized piece of equipment (about the size of a lunch-box DVM), but it's definitely indicated for this type of experiment.
 
We did this experiment a few years ago, I'm just wondering if there was any feasible way to do it in a school lab. The science equipment in colleges is pretty poor. The highest voltage that we could generate with standard equipment would be about 50V. Even if I had an extremely accurate pico-ammeter, I'd need to be able to actually pass a current through the brick. The electrical resistivity of brick is much higher than the electrical resistivity of air, so the electric current is much more likely to arc over the brick through the air. To even do such a thing, I'd need like 300kV or something. In a school lab, that's impossible.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top