Resistor connected in series with a capacitor?

AI Thread Summary
In a series RC circuit with a 3uF capacitor and a 1-ohm resistor connected to a 6V EMF, the potential difference across the resistor depends on the time since the circuit was energized. Initially, when the capacitor is uncharged, the voltage across the resistor is equal to the EMF, but as the capacitor charges, the voltage across the resistor decreases. After a long time, the capacitor becomes fully charged, resulting in zero current and thus zero voltage across the resistor. The voltage across the capacitor and resistor can be calculated using the formulas V(c) = Vcc (1-e^(-t/rc)) and V(r) = Vcc * e^(-t/rc). Understanding the time factor is crucial for determining the voltage across the resistor in this circuit.
gunblaze
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Pls help..

If i have a capacitor of capacitance 3uF connected in series with a resistor, what will the potential difference across the 1ohm resistor when the EMF is 6V?

Is the answer a zero? If yes, why? is it becoz the capacitor itself have make the circuit a open circuit such that no current will be able to reach the resistor? If no, why?

Thanks
 
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My question would be at what time? This is a series RC circuit, and the voltages depend on how much time passes after you apply the 6 volts.

V(c) = Vcc (1-e^-(t/rc))

V(r) = Vcc * e^-(t/rc)
 
if it was stated that the capacitance were charged fully? No time were stated.
 
Well.. there must be some kind of qualification as to time. If the circuit has been connected a very long time, you could solve it by making t very very large. The equations do model the behavior of the circuit quite nicely.
 
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