Resolution of Optical Instruments Question

AI Thread Summary
A 3.1 cm tall object is positioned 26 cm to the left of a lens with a 13 cm focal length, followed by a second lens with an 8 cm focal length located 42 cm to the right of the first lens. The thin lens equation is applied, resulting in an image distance (s') of -8.67 cm for the first lens, indicating the image is virtual and located to the left of the first lens. The user attempts to find the image distance for the second lens by adjusting the distance calculations but is encountering difficulties. The final calculations needed include determining the distance from the second lens to the image and calculating the image height.
smoics
Messages
28
Reaction score
0

Homework Statement


A 3.1 cm--tall object is 26 cm to the left of a lens with a focal length of 13 cm. A second lens with a focal length of 8.0 cm is 42 cm to the right of the first lens.

Homework Equations


1/s + 1/s' =1/f
M=-s'/s and I'll have to multiply the two M's together to get the final M.

The Attempt at a Solution


I drew out a ray diagram. Maybe my signs are wrong?? 1/-26 + 1/s' = 1/13. s'=-8.67. This would be to the left of the first lens, so I tried doing 42+ s' and also 42-s' to use in the thin lens equation the second time (As the distance from lens 2), but none of my answers are working...?
 
Physics news on Phys.org
Calculate the distance between image and the second lens.
and Calculate the image height.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
5
Views
1K
Replies
2
Views
842
Replies
3
Views
2K
Replies
2
Views
1K
Replies
1
Views
2K
Replies
5
Views
1K
Replies
4
Views
4K
Replies
2
Views
3K
Back
Top