Resolving 3D Forces for Determining xyz Components

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The discussion revolves around resolving a force of 200 N into its xyz components, with the force being at 35 degrees from the horizontal when viewed face-on and 12 degrees from the horizontal when viewed from above. The user initially calculated the components but found discrepancies when checking against the magnitude of the force. It was clarified that the force F is the same in both diagrams, but the user misrepresented the angle in the second diagram. After realizing the error, the user corrected the angle to 102 degrees, which aligned the calculations properly. This adjustment resolved the confusion regarding the force components.
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Hi, I am trying to resolve a force into xyz components and I think I'm getting a bit confused.

When viewed face on the force is 35 degrees from the horizontal.

When viewed from above the force is at 12 degrees from the horizontal (not sure if one would refer to it as the horizontal but see the attached figure for clarity).

The magnitude of the force is 200 N.

The attempt at a solution:

Fy= (200)cos55 = 114.72 N
Fx=(200)cos35 = 163.83 N
Fz=(200)cos12= 195.63 N

However, F should equal sqrt{(Fx2+Fy2+Fz2)} but it does not, so I know I'm going wrong somewhere. Any hints?
 

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Hi, LukaD.

The two projections both have the force labeled as F. But is F in any of them the actual, full magnitude of 200N?
 
F is the full magnitude yes. F is the same force in both diagrams viewed from different angles.
 
Heh, I wasn't actually asking a question. I was pointing out the mistake. Can you take it from here, or do you need another clue?
 
Oh I see, I drew the diagram wrong, the line representing F in the second diagram should actually be the xy plane, so it's 102 degrees not 12. Is that right? It seems to work out!
 
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