Resolving Power and minimum seperation

In summary, using a telescope with a circular aperture of 2.42 m and light with a wavelength of 547 nm, the minimum separation between two stars that are 10^22 m away from us would be 2.758*10^15 m in order for us to recognize them as two separate stars. Additionally, if the pupils of our eyes are 6.7 mm in diameter and the index of refraction is 1.36, a car's taillights that are 1.27 m apart would appear as a single spot of light when the car is 14.2 km away, emitting a wavelength of light in vacuum.
  • #1
ahazen
49
0
(a) Two stars are photographed utilizing a telescope with a circular aperture of diameter of 2.42 m and light with a wavelength of 547 nm. If both stars are 1022 m from us, what is their minimum separation so that we can recognize them as two stars (instead of just one)?

theta=1.22* lambda/D

(b) A car passes you on the highway and you notice the taillights of the car are 1.27 m apart. Assume that the pupils of your eyes have a diameter of 6.7 mm and index of refraction of 1.36. Given that the car is 14.2 km away when the taillights appear to merge into a single spot of light because of the effects of diffraction, what wavelength of light does the car emit from its taillights (what would the wavelength be in vacuum)?
 
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  • #2
What do you think?
 
  • #3
Just to check my own understanding. Is the answer to part a) 2.818*10^-4m? Come to think off it, can the star be only 1022m away from us?

Delzac
 
  • #4
Delzac said:
Just to check my own understanding. Is the answer to part a) 2.818*10^-4m? Come to think off it, can the star be only 1022m away from us?
No, if you were only around 1 km from the center of a star, you would be inside the star's core. Your body would be crushed to a size of a small stone, under such extreme temperature and pressure that the atoms in your body would lose their electrons and the nuclei would fuse to form new elements. You would become an extraordinarily dense, hot mishmash that is barely even comprehensible by most humans.

Perhaps you mean the distance of the stars is 1 x 1022 m away from us?
 
  • #5
If the distance is 10^22m, then will be answer be 2.758*10^15m?

delzac
 
  • #6
ok:) thank you:)
 

What is Resolving Power?

Resolving Power is a measure of the ability of a scientific instrument, such as a microscope or telescope, to distinguish between two closely spaced objects. It is also known as angular resolution or spatial resolution.

How is Resolving Power calculated?

Resolving Power is calculated by dividing the wavelength of the incident light by the numerical aperture of the instrument. The higher the numerical aperture, the better the resolving power.

What is the minimum separation needed for Resolving Power?

The minimum separation needed for Resolving Power is equal to half of the wavelength of the incident light. This is known as the Rayleigh Criterion, and it ensures that two objects can be distinguished as separate entities.

What factors affect Resolving Power?

The main factors that affect Resolving Power are the wavelength of the incident light, the numerical aperture of the instrument, and the quality of the optics. Other factors such as atmospheric conditions and instrument alignment can also have an impact.

How is Resolving Power used in scientific research?

Resolving Power is crucial in many fields of scientific research, such as astronomy, biology, and materials science. It allows scientists to study and analyze small and distant objects, leading to a better understanding of the world around us.

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